A falsidical paradox
[^ represents to the power of and (d/dx) represents differentiation with respect to x]
x^2 = x + x + ... + x (x times)
=> (d/dx)(x^2) = (d/dx)(x + x + ... + x)
=> 2x = 1 + 1 + ... + 1 (x times)
=> 2x = x
Of course, this is wrong. Find the bug in the argument. Also explain why we are getting '2' particularly.
posted by Sids @ 4:34 PM
6 comments
6 Comments:
discontinuous functions can't be differentiated..
-Subhash
@subhash,
Neither of the functions above are discontinuous.
They expressions taken individually are continouous but the equation holds good only for +ve integer values. That makes the expression discontinous
-Subhash
@subhash,
That is correct but only part of the answer. Why the '2'? That's the main question.
because x^2 is symmetric about origin. So, the area under the curve is twice that of the area covered by the function on right hand side.
--vaasu
long time no post.we want NEWPOST
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